How To - Masses & Solutions 1 - Chemistry

Hey there, I have had a lot of trouble with this one - probably also because I didn't practice so much...
Making solutions and solvents of solutions is difficult, to me.
So today we are gonna fix that ._.

To calculate solutions with a concentration, there is a very simple formula the so called
Andreas-Cross, this is what it looks like:


We have two overlapping arrows with the target solution (Sol Z) and it's concentration we want to produce in the middle.
The left side shows our base material (Solution I (Sol X), Solution II (Sol Y) and their respective concentrations) and on the right we will get how many parts of each solution we need to create Sol Z, by subtracting the percentage from Sol Z from Sol X / Sol Y and taking the modulus from that.
*BUTT* Take a good look at the picture - Sol Y tells you how many parts of Sol X you need and the other way too!!

1. Example
Sol X = 35% Acid; Sol Y = 15% Acid
We want a 22% Solution mixed from Sol X and Sol Y


Tadaa - if you got to here, congrats. We need 7 parts of Sol X and 13 parts of Sol Y - the parts total to a complete amount of 20.
If you want to get 1kg of the 22% acid, divide 1000g by the total of parts and multiply it with how many parts you need for each material


This works with water too - if you want to dilute an acid i.e., just fill in 0% for the water and start calculating :)

Comments

Post a Comment

Popular posts from this blog

How To - Citric Acid Cycle

Image
The citric acid cycle is one of the central logistical hub in our metabolism. It provides oxidative breakdown for organic substances, energy by releasing CO2 and H2O from Acetyl-CoA and so on. There are 10 basic steps to the cycle and its goal is to catalyze the condensation of Oxalacetate to Citrate. I will list the  intermediates of this reaction and their respective enzymes , as well as their components : Citrate  + Aconitase -> cis-Aconitate   ( H20) cis-Aconitate + Aconitase ->  Isocitrate    ( H20) Isocitrate  + Isocitrate-dehydrogenase -> Oxalsuccinate    (NAD+, NADH) Oxalsuccinate  + Isocitrate-dehydrogenase -> Alpha-ketoglutaric-acid   (CO2) Alph a-ketoglutaric-acid  + alpha-ketoglutarate-dehydrogenase-complex -> Succinyl-CoA   (CoA, NAD+, CO2, NADH/H+) Succinyl-CoA  + Succinyl-CoA-Synthase -> Succinate  (GDP, ADP, GTP, ATP) Succinate  + Succinate-dehydrogenase -> Fumarate   (FAD, FADH2) Fumarate  + Fumaras
Read more

How To - CYK Algorithm

Image
In this quick post I try to explain the basics of the Cock-Younger-Kasami ( CYK ) Algorithm to you. This shouldn't take more than 15min for you to understand, since I am terrible at logic and math related studies - if I could do it so can you :D The CYK is a theoretical construct that can be used to find context free languages by feeding grammar and its production rules into a table and see wether a word from the language you wish to identify, matches up with these rules. To make this process run smooth, the production rules must be formatted in such way that it matches Chomsky Normal Form ( CNF ) standards; on the left hand side of a production rule stands a non-terminal symbol (a variable) on the right hand side of a production rule there can be maximal 2 non-terminals or 1 terminal symbol (a symbol that represents a constant value) but never non-terminals and terminals mixed For my course I worked through an example step by step, we started out with 3 production rules: A
Read more

How To - Determinants of Matrices

Image
The determinant of a matrix is very useful and commonly asked for in exams. With it, you can determine if a matrix is invertible (thus find the inverse for sure, without wasting tons of precious time in an exam) and it's a sure way to get points even if you are pretty hopeless and just want to pass There are three basic cases for matrices, dimensions 2x2 , 3x3 and dimensions 3< . Results for the three exercises will be posted at the end. Tipp : a matrix can only be inverted if the determinant does not equal 0 ! In the case of matrix A (2x2) the main- minus minor-diagonal formula applies; with upper left times lower right, minus upper right times lower left. For example B (3x3) it becomes more complicated. We can apply the rule of Sarrus ( Wikipedia ). For that, we replicate the first two columns to the right side. Now we create the main and minor diagonals, as seen in the picture below: After this, we subtract the sum of the minors from the sum of the
Read more