### How To - Masses & Solutions 1 - Chemistry

Hey there, I have had a lot of trouble with this one - probably also because I didn't practice so much...

Making solutions and solvents of solutions is difficult, to me.

So today we are gonna fix that ._.

To calculate solutions with a concentration, there is a very simple formula the so called

We have two overlapping arrows with the

The left side shows our base material

*BUTT* Take a good look at the picture -

1. Example

Sol X = 35% Acid; Sol Y = 15% Acid

We want a 22% Solution mixed from Sol X and Sol Y

Tadaa - if you got to here, congrats. We need

If you want to get

This works with water too - if you want to dilute an acid i.e., just fill in 0% for the water and start calculating :)

Making solutions and solvents of solutions is difficult, to me.

So today we are gonna fix that ._.

To calculate solutions with a concentration, there is a very simple formula the so called

**Andreas-Cross**, this is what it looks like:**target solution (Sol Z)**and it's concentration we want to produce in the middle.The left side shows our base material

**(Solution I (Sol X), Solution II (Sol Y) and their respective concentrations)**and on the right we will get how many parts of each solution we need to create**Sol Z**, by subtracting the percentage from**Sol Z**from**Sol X / Sol Y**and taking the modulus from that.*BUTT* Take a good look at the picture -

**Sol Y**tells you how many parts of**Sol X**you need and the other way too!!Sol X = 35% Acid; Sol Y = 15% Acid

We want a 22% Solution mixed from Sol X and Sol Y

**7 parts of Sol X**and**13 parts of Sol Y**- the parts total to a complete amount of**20**.If you want to get

**1kg of the 22% acid**, divide**1000g**by the total of parts and multiply it with how many parts you need for each material
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